Question

6. Aball dropped from the top of a building reaches ground in 6 seconds. Find the velocity
with which it will hit the ground if value of gis 9.8 ms'.
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Answer 1

Step-by-step explanation:

Answer:

In the present event a ball is being dropped (the term means that initial velocity=0)

from a height h

h = 19.6 m = 2 times the numerical value of g, the acceleration due to gravity

we know how accelerations operate ..it will add per sec the value of g to the velocity

v = g.t

but the time taken to cover h =19.6 m ; using h = (1/2) g . t^2

t = sqrt ( 2.h /g) = 2

so the velocity of striking the ground v = 9.8 m/s^2 x 2 s = 19.6 m/

Explanation: