Question

6. ABC is a right-angled triangle and O is the mid point of the side opposite to the right angle. Explain why O is equidistant from A, B and C. (The dotted lines are drawn additionally to help you. Refer to the attachment)
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please don't give irrelevant answers otherwise they will be reported.​

Answer 1

Answer:

hey here is your answer

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Step-by-step explanation:

so here O is the centre of quadrilateral ABCD

so here triangle ABC is a right angled triangle right angled at B

so side opp. to angle B is AC

thus here it is said that O is midpoint of AC

so thus then

AO=OC

moreover as O is O centre of quadrilateral ABCD

it must and must be also midpoint of BD

thus BO=OD

Hence O is not only equidistant from three vertices A,B,C but also from all four vertices ie A,B,C and D

hope it helped u a lot