Question

6. ABC is a right-angled triangle. Angle ABC = 90°,
AC = 25 cm and AB = 24 cm. Calculate the area of a
∆АВС.
the ans is 84 cm^2 but how​

Answer 1

Answer:

Acc. to Pythagoras theorem,

AC²=AB²+BC²

25²=24²+BC²

625-576=BC²

49=BC²

BC=7cm

Area of triangle=1/2bh

=1/2X24X7 cm²

=12X7 cm²

=84 cm²

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Answer 2

Given,

A right-angle triangle ΔABC

∡ABC = 90°

AC = 25cm

AB =24cm

To Find,

The area of right-angle ΔABC

Solution,

Given that,

ABC is a right-angle triangle.

AC = 25cm

AB = 24cm  

According to pythagoras theorem

" The hypotenuse of the triangle is equal to the square root of the sum of the square of the other side".

Here side AC is the hypotenuse of the ABC triangle.

SO,

AC² = AB² +BC²

25² = 24² + BC²

BC² =625 - 576

BC² = 49

BC = √49

BC = 7cm

In triangle ABC base b = 7cm

Height h = 24cm

Triangle's area = 1/2×b×h

A = 1/2×7× 24

A =12× 7

A = 84cm²

The triangle's area is 84cm².