6. ABCD is a parallelogram AP and CQ are
perpendiculars drawn from vertices A and C on
diagonal BD (see figure) show that
(i) AAPB = ACQD
EE
(ii) AP=CQ
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Step-by-step explanation:
दिया है :
ABCD एक समांतर चतुर्भज है तथा AP और CQ शीर्षों A और C से विकर्ण BD पर क्रमशः लम्ब हैं।
सिद्ध करना है :
(i) ΔAPB ≅ ΔCQD
(ii) AP = CQ
हल:-
(i) ΔAPB तथा ΔCQD में,
∠ABP = ∠CDQ (∵ AB || CD , एकांतर अंत: कोण))
∠APB = ∠CQD (90°)
AB = CD (समांतर चतुर्भुज की भुजाएं)
∴ ΔAPB ≅ ΔCQD (AAS सर्वांगसमता नियम द्वारा )
(ii) ∵ ΔAPB ≅ ΔCQD
∴ AP = CQ (CPCT द्वारा)
इति सिद्वम्
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