Question

6) ABCD is a parallelogram with area 80 sq.cm. The diagonals AC and BD intersect at
O.P is the mid-point of OA. Calculate ar (BOP).​

Answer 1

20 sq. cm because there are four parts 80 divide by 4 so 20 sq.cm

Answer 2

Step-by-step explanation:

Area of triangle AOB = 80/4 = 20sq.cm

.{ diagonals of a parallelogram divide it into four triangles of equal area}

so area of triangle BOP = 20/2

= 10sq.cm { p is the midpoint of AO}