Question

6 & 7 term of an Ap is 19 & 41 find 40 term

Answer 1

Answer:

a6 = 19

a7 = 41

common difference (d)= a7 - a6 = (41 - 19) = 22

a6 = a + 5d

19 = a + 110

a = 19 - 110

a = -91

a40 = a + 39d

= -91 + (39 × 22)

= -91 + 858

a40 = 767.

Hope this helps you☺

Answer 2

$\huge\underline\bold\orange{ANSWER :}$

Given that,

6 & 7 term of an Ap is 19 & 41 find 40 term

Let,

• a6 = 19
• a7 = 41

We can write,

• a6 → a + 5d = 19....... (1)

• a7 → a + 6d = 41....... (2)

Subtract the equations (1) & (2), we get

➡ - d = - 22

➡ d = 22

$\boxed{∴ d = 22 }$

Now, substitute d in the equation (1), to get a

➡ a + 5(22) = 19

➡ a + 110 = 19

➡ a = 19 - 110

➡ a = - 91

$\boxed{∴ a = - 91 }$

Now, to find the value of a40,

• a40 = a + 39d

Substitute the values of a & d

➡ -91 + 39(22)

➡ - 91 + 858

➡ 767

$\boxed{∴ a40 = -767 }$

∴ HENCE, IT IS SOLVED...

Step-by-step explanation:

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