Question

6. An air-plane flying in space is at a
position (in km) (2, -3, 5).
After some time, it arrives at the position (in
km) (4, 5, -6).
What is the displacement of the air-plane
(in km) during this
period.
(6^1 + 2^j – ^k) km
(2^i + 2^j - 1^k) km
(2^1 + 8) - ^k) km
(2^1 + 8^j - 114k) km​

Answer 1

Answer:

this could be done by simple vector

by subtracting the first displacement from second in form of I j k