Math, asked by sdmdhussain91, 2 months ago

6. An analysis of daily wages of casual labourers in two firms A and B, belonging to the
same industry, gives the following result:
Firm A
Firm B
50
60
No. of workers
Average daily wages (in 3)
S.D.
113
120
6.5
8.2
Find the mean and S.D. of wages of all casual labourers in the two firms taken together.​

Answers

Answered by surajkumarkumar59351
4

Answer:

(i) Number of wage earner in firm A=586

Mean of monthly wage of firm A=Rs5253

Mean of monthly age of firm A =

No. of wage earners in firm A

Total amount paid

5253=

586

Total amount paid

Total amount paid by Firm A =5253×586

Number of wage earner in firm B=648

Mean of monthly wage of firm B=Rs5253

Mean of monthly age of firm B =

No. of wage earners in firm B

Total amount paid

5253=

648

Total amount paid

Total amount paid by Firm B =5253×648

Clearly, firm B paid larger amount as monthly wage.

(ii) Variance of the distribution of wages in firm A (σ

1

2

)=100

∴ Standard deviation of the distribution of wages in firm A(σ

1

)=

100

=10

Variance of the distribution of wages in firm B(σ

1

2

)=121

∴ Standard deviation of the distribution of wages in firm B(σ

2

)=

121

=11

The mean of monthly wages of both the firms is same i.e.5253. So, the firm with greater standard deviation will have more variability.

Thus firm B has greater variability in the individual wages

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