6. An eighty meter long train crossed
a 120 meter length platform in
1 min. 20 sec. The speed of that
train is-
SAT 12 km./hr. (B) 9 km./hr.
(C) 45 km./hr. (D) 100 km./hr.
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speed =distance/time
distance=80+120=200mtrs=.2km
time=80sec=80/3600hr=1/45hr
speed=(2×45)/10=9km/hr
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