6. An electric bulb is rated 220V and 100W. when it is operated on 110V, the power consumed will be
(b)751
(e 50W
(d)25W
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Answer:
Explanation:
Let the resistance be R
Given power=100W
V^2/R=100
R=220*220/100 ohms
R=484 ohms
Power delivered now=V^2/R=110*110/22*22
Power=5*5=25 Watt
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