Question

6. An electric dipole is placed at an angle 60' with an electric field of strength 4*105 N/C. It experiences
a torque equal to 8 3 Nm. Calculate the charge on the dipole. if dipole is of length 4 cm
(A) 10^-1C (8) 10^-2C C) 10^-3C D) 10^-4C.

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Answer 1

Answer:

we have to calculate charge so we put all the values in formula to get the answer

Answer 2

Given :

Electric field , $E=4\times 10^5\ N/C$ .

Angle between field and torque , $\theta=60^o$ .

Torque experienced , $\tau=83\ Nm$ .

Length of dipole , l = 4 cm = 0.04 m .

To Find :

The charge on the dipole .

Solution :

We know , torque on dipole due to electric field is given by :

$\vec{\tau}=\vec{P} \times \vec{E}\\\tau=PE\ sin\ \theta$       ......( 1 )

Here , P is dipole moment and it is given by :

$P=ql\\P=q\times 0.04$

Also , $sin\ \theta=sin \ 60^o=\dfrac{\sqrt{3}}{2}$

Putting , value of P and E in equation 1

We get :

$\tau=PE\ sin\ \theta\\83=q\times 0.04\times 4\times 10^5\times \dfrac{\sqrt{3}}{2}\\\\q=\dfrac{83}{ 0.04\times 4\times 10^5\times \dfrac{\sqrt{3}}{2}}\\\\q=6\times 10^{-3}\ C$

Therefore , charge of dipole is $6\times 10^{-3}\ C$ .

Learn More :

Electrostatics

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