Question

6. An electric heater of resistance 8 2 points
ohm draws 15 A from the service
mains 2 hours. Calculate the rate at
which heat is developed in the
heater?
1800 J​

Answer 1

Answer:

1800j

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Answer 2

Answer:

V= I×R

V=82×15

= 1230v

Energy = P×t

E=V×I×t

E=1230×15×2

1230×30

= 36900joules