6. An object 4 cm in size is placed at a distance of 25 cm from a concave mirror of focal length 15 cm. Find the position, nature and height of the image.
Answers
Answered by
2
Explanation:
Height of object- 4cm (ho)
Object Distance- -25 cm (u)
Focal Length- -15cm (f)
Using mirror formula,
1/f - 1/u = 1/v
-1/15 + 1/25 = 1/v
- 5 +3/ 75 = 1/v
-2/75 = 1/v
v= -75/2 = -37.5
So, the image will form on the same side of the object placement.
m= -v/u = hi/ho
-(-37.5)/-25 = hi/4
- 1.5 x 4 = hi
hi= -6 cm
So, the image formed is real, inverted and highly magnified. Image Height is 6 cm.
Answered by
0
Answer:
(6cm)
Explanation:
HEIGHT OF OBJECT = 4cm (HO)
OBJECT OF DISTANCE = -2cm (U)
FOCAL LENGTH = -15cm (F)
Using Formula.. (mirror)
1/f - 1/u = 1/v
-1/15 + 1/25 = 1/v
-5+3/75 = 1/v
-2/75 = 1/v
v = -75/2
= (-37.5)
Hence,,. The image will form on the same side...
m= -v/u = hi/ho
-(-37.5)/(-25) = hi/4
-1.5×4 = hi
hi = -6cm
So,,. the image formed is real, inverted and highly magnified...
Image Height Is - 6cm
Hope its help uu...
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