Question

6. An object is placed at a distance of 50 cm from a concave lens of focal length the 30 cm.
Find the nature and position of the image.

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Answer 1

An object is placed at a distance of 50 cm from a concave lens of focal length 30 cm. How can you find the nature and the position of the image? The nature and approximate position is trivial. ... v = -150/8 or 18.75 from the lens, virtual.

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Answer 2

Answer:

Step-by-step explanation:

u=50cm,

f=30cm

1/f=1/v  -   1/u

1/30  +  1/-50  = 1/v

(5 + 3)/-150 = 1/v

-150/8 = v

v=-18.75 cm

the image formed is virtual.

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