Question

6. An object of mass 60 kg is accelerated from 6 m/s to 12 m/s in 4 s.
Find its acceleration and the magnitude of force acting on it
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Answer 1

Answer:

Acceleration = 1.5 m/s²

Force = 60 Newtons

Explanation:

Given:

• Mass of the object = m =  60 kg
• Initial velocity of the object = u = 6 m/s
• Final velocity of the object = v = 12 m/s
• Time = t = 4 seconds

To find:

• Acceleration of the object
• Force acting on the object

acceleration = (v-u)/t

acceleration = (12-6)/4

acceleration = (6)/4

Acceleration = 1.5 m/s²

The acceleration of the object is equal to 1.5 m/s²

Force = Mass×Acceleration

Force = 60×1.5

Force = 90 Newtons

The force is equal to 90 Newtons

More:

• First equation of motion = V=u+at
• Second equation o motion = s=ut+$\frac{1}{2}$at²
• Third equation of motion = v²-u²=2as