6. An urn contains 2 white, 3 black, 4 red, 5 green and 7 blue balls. What is the probability of
getting
(a) a white ball? (b) a red ball?
(c) a green ball?
(d) a blue ball?
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Answer:
total no. of balls=2+3+4+5+7
=21
a) probability of getting white ball
no. of white ball/total no. of balls
= 2/21
b) probability of getting red ball
= no. of red ball/total no. of balls
= 4/21
c) probability of getting green ball
= no. of green ball/total no. of balls
= 5/21
d) probability of getting blue ball
= no. of blue ball/total no. of balls
=7/21
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