6 and 7 factorise this question
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(1) 9x2y2-16
=(3xy)2_(4)2
=(3xy+4)(3xy-4)
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Answer:
vi) (3xy+4)(3xy-4)
vii)(x-y+z)(x-y-z)
Explanation:
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We know the algebraic identity:
a²-b²=(a+b)(a-b)
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vi) 9x²y²-16
= 3²x²y²-4²
= (3xy)²-4²
= (3xy+4)(3xy-4)
vii) (x²-2xy+y²)-z²
=(x-y)²-z²
= (x-y+z)(x-y-z)
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