Math, asked by divyanshchaudhary422, 17 hours ago

6. Annual exam class 3 (math) How lon the railway station 6.30 p.m. The train is supposed to come at 19 45
How long does he have to wait?​

Answers

Answered by itzmankiratjatt
2

Answer:

1 hr

as Smirti arrives at the railway station at 6:40 pm the train is supposed to come at 19:40

19:40 time is equivalent to 19:40 - 12:00 = 7:40 PM

so waiting time will be 7:40PM - 6:40PM = 1 hr

here we assumed that times mentioned are of same day.

or we can solve it by like that

6:40 PM time is 12 hr format .we can convert into 24 hr format like this

6:40 + 12:00 = 18:40

so waiting time = 19:40 - 18:40 = 1:00

1 hr

Step-by-step explanation:

Answered by Rina86169
3

Answer:

Answer:

1 hr

as Smirti arrives at the railway station at 6:40 pm the train is supposed to come at 19:40

19:40 time is equivalent to 19:40 - 12:00 = 7:40 PM

so waiting time will be 7:40PM - 6:40PM = 1 hr

here we assumed that times mentioned are of same day.

or we can solve it by like that

6:40 PM time is 12 hr format .we can convert into 24 hr format like this

6:40 + 12:00 = 18:40

so waiting time = 19:40 - 18:40 = 1:00

1 hr

Step-by-step explanation:

Similar questions