6. Annual exam class 3 (math) How lon the railway station 6.30 p.m. The train is supposed to come at 19 45
How long does he have to wait?
Answers
Answer:
1 hr
as Smirti arrives at the railway station at 6:40 pm the train is supposed to come at 19:40
19:40 time is equivalent to 19:40 - 12:00 = 7:40 PM
so waiting time will be 7:40PM - 6:40PM = 1 hr
here we assumed that times mentioned are of same day.
or we can solve it by like that
6:40 PM time is 12 hr format .we can convert into 24 hr format like this
6:40 + 12:00 = 18:40
so waiting time = 19:40 - 18:40 = 1:00
1 hr
Step-by-step explanation:
Answer:
Answer:
1 hr
as Smirti arrives at the railway station at 6:40 pm the train is supposed to come at 19:40
19:40 time is equivalent to 19:40 - 12:00 = 7:40 PM
so waiting time will be 7:40PM - 6:40PM = 1 hr
here we assumed that times mentioned are of same day.
or we can solve it by like that
6:40 PM time is 12 hr format .we can convert into 24 hr format like this
6:40 + 12:00 = 18:40
so waiting time = 19:40 - 18:40 = 1:00
1 hr
Step-by-step explanation: