6 Apple 5 mango cost 60 , 8 Apple 9 mango cost 80, find cost of 1 Apple and 1 mango
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Hi ,
Let cost of 1 apple = Rs x
cost of 1 mango = Rs y
According to the problem given ,
6x + 5y = 60 ---( 1 )
8x + 9y = 80 -----( 2 )
multiply equation ( 2 ) with 6 and
multiply equation ( 1 ) with 8 , we get
48x + 54y = 480 ---( 3 )
48x + 40y = 480 ---( 4 )
subtract ( 4 ) from ( 3 ) , we get
14y = 0
y = 0
Substitute y = 0 in equation ( 1 ) , we get
6x + 5 × 0 = 60
6x = 60
x = 60/6
x = 10
Therefore ,
cost of 1 Apple = Rs x = Rs 10
cost of 1 Mango = Rs y = 0
I hope this helps you.
: )
Let cost of 1 apple = Rs x
cost of 1 mango = Rs y
According to the problem given ,
6x + 5y = 60 ---( 1 )
8x + 9y = 80 -----( 2 )
multiply equation ( 2 ) with 6 and
multiply equation ( 1 ) with 8 , we get
48x + 54y = 480 ---( 3 )
48x + 40y = 480 ---( 4 )
subtract ( 4 ) from ( 3 ) , we get
14y = 0
y = 0
Substitute y = 0 in equation ( 1 ) , we get
6x + 5 × 0 = 60
6x = 60
x = 60/6
x = 10
Therefore ,
cost of 1 Apple = Rs x = Rs 10
cost of 1 Mango = Rs y = 0
I hope this helps you.
: )
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