Question

6 are consecutive numbers is 540 then what is the sum of smallest and the largest number of the series​

Answer 1

❏ Solution:-

Let , the consecutive 6 odd numbers series is ,

(x-6), (x-4) , (x-2) , x , (x+2) , (x+4)

Now , according to the question the sum of these 6 consecutive odd numbers is 540 ,

Hence ,

$\implies\sf{\ \ {(x-6)+(x-4)+(x-2)+ x +(x+2)+(x+4)=540}}$

$\implies\sf{\ \ {6x-6=540}}$

$\implies\sf{\ \ {6x=540+6}}$

$\implies\sf{\ \ {6x=546}}$

$\implies\sf{\ \ {x=\dfrac{\cancel{546}}{\cancel6}}}$

$\implies\boxed{\sf{\ \ {x=91}}}$

∴ Therefore the smallest number is

=91-6

=85

and the largest number is

=91+4

=95

∴ The sum of the smallest number and the largest number is = 85+95=180

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