Question

6. (ax + ay) +a + 4b =0, 2 (bx + ay ) +b-4a=0​

Answer 1

Answer:

for 1st

ax+ ay+a+4b=0

for 2nd

2bx+2ay+b-4a=0

from eq1n2

ax+ay+a+4b=2bx+2ay+b-4a

ax+ay-2ay+a+4a+4b-b-2bx

ax-ay+5a+3b-2bx

a(x-y+5)+b(3-2x)