6(ax+by)=3a+2b 6(bx-ay)=3b-2a
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6(ax+by) =3a+2b , 6(bx-ay)=3a-2b
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6(ax+by) =3a+2b , 6(bx-ay)=3a-2b
Posted by Rohan Sethi 1 year ago
CBSE > Class 10 > Mathematics
1 answers
Sia 1 year ago
6(ax + by) = 3a + 2b
6ax + 6by = 3a + 2b.........(i)
6(bx - ay) = 3b - 2a
6bx - 6ay = 3b - 2a.........(ii)
Multiplying (i) by a and (2) by b,
So, 6a2x + 6aby = 3a2 + 2ab .......... (iii)
And 6b2x - 6aby = 3b2 - 2ab ......... (iv)
Add (iii) and (iv), we get
6a2x + 6aby + 6b2x - 6aby = 3a2 + 2ab + 3b2 - 2ab
⇒ 6a2x + 6b2x = 3a2 + 3b2
⇒6 (a2x + b2x) = 3(a2 + b2)
⇒x=3(a2+b2)6(a2+b2)=36=12x=3(a2+b2)6(a2+b2)=36=12
Substituting x=12x=12 in (i),we get
6a×12+6by=3a+2b6a×12+6by=3a+2b
⇒ 3a + 6by = 3a + 2b
⇒ 6by =3a + 2b -3a
⇒ 6by = 2b
⇒ y=2b6b=13y=2b6b=13
Hence, the solution is x=12,y=13