Question

6. Balance the following chemical equations.
(a) HNO, + Ca(OH), Ca(NO), +H,O
(b) NaOH + H, SO, → Na, SO, +H2O
(c) NaCl + AgNO, → AgCl + NaNO,
3​

Answer 1

Answer:

hope it helps you please mark as brainlist

Step-by-step explanation:

Hydrogen + Chlorine → Hydrogen chloride

(b) Barium chloride + Aluminium sulphate → Barium sulphate + Aluminium chloride

(c) Sodium + Water → Sodium hydroxide + Hydrogen

Ans: (a) H2 (g) + Cl2 (g) → 2HCl (g)

(b) 3BaCl2 (s) + Al2(SO4)3 (s) → 3BaSO4(s) + 2AlCl3 (s)

(c) (c) 2Na(s) + 2H2O (l) → 2NaOH (aq) + H2 (g)

Answer 2

CORRECT QUESTION:

Balance the following chemical equations

$(a) HNO_3 +Ca(OH)_2 \rightarrow Ca(NO3)_2 + H_2O\\(b) NaOH + H_2SO_4 \rightarrow Na_2SO_4 + H_2O\\(c) NaCl + AgNO_3 \rightarrow AgCl + NaNO_3$

ANSWER:

$(a) 2 \:HNO_3+ Ca(OH)_2 \rightarrow Ca(NO3)_2 + 2 \:H_2O \\(b) 2\: NaOH + H_2SO_4 \rightarrow Na_2SO_4 + 2 \:H_2O \\(c) NaCl + AgNO_3 \rightarrow AgCl + NaNO_3$

____________________________________

EXPLANATION:

a) First to balance the H add 2 Before $HNO_3$, WE GET

$2\:HNO_3 +Ca(OH)_2 \rightarrow Ca(NO3)_2 + H_2O$

NOW LEFT SIDE WE HAVE 4 HYDROGENS. TO BALANCE IT ADD 2 BEFORE $H_2O$ ON RIGHT SIDE, WE GET

$2\: HNO_3 +Ca(OH)_2 \rightarrow Ca(NO3)_2 + 2\: H_2O$

YOU CAN ALSO NOTICE THE NUMBER OF OXYGEN, NITROGEN, CALCIUM ATOMS ARE BALANCED ON BOTH THE SIDES.

____________________________________

b) TO BALANCE Na ON BOTH SIDES, ADD 2 BEFORE NaOH ON LEFT SIDE.

$2 \:NaOH + H_2SO_4 \rightarrow Na_2SO_4 + H_2O$

SULPHUR AND SODIUM ARE BALANCED.

TO BALANCE HYDOGEN AND OXYGEN ADD 2 BEFORE $H_2O$ IN RIGHT SIDE.

FINALLY WE WILL GET

$2 \:NaOH + H_2SO_4 \rightarrow Na_2SO_4 + 2 \:H_2O$

____________________________________

c) NUMBER OF SODIUM, SILVER, NITROGEN, OXYGEN AND CHLORINE ARE ALREADY BALANCED.

HENCE THE FINAL EQUATION IS

$NaCl + AgNO_3 \rightarrow AgCl + NaNO_3$

____________________________________