Question

6. BC is the diameter of the circle with centre ‘o’, AD is tangent drawn to the circle at D,Angle ADC 110 Degree, Then Find the angle DOC?

Answer 1

Answer:

Electromagnetic radiation, in classical physics, the flow of energy at the universal speed of light through free space or through a material medium in the form of the electric and magnetic fields that make up electromagnetic waves such as radio waves, visible light, and gamma rays.

Answer 2

Answer:

140°

Step-by-step explanation:

Refer the attached image

We know,

The line joining the point of intersection of the tangent of the circle to the radius is perpendicular to the tangent.

Hence,

∠ODA = 90°

Also,

∠ODC= ∠ADC - ∠ODA

= 110° - 90°

=20°

Now,

OD = 0C (Radii)

∠ODC = ∠OCD = 20° (Isos. Δ property)

In ΔODC,

∠ODC + ∠OCD + ∠DOC = 180°

20° + 20° + ∠DOC = 180°

∴∠DOC = 140°