6 boys and 6 girls are arrange in a row at random by the probability that boys and girls are alternate
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6 boys and 6 girls sit in a row at random.
Then, the total number of arrangements of 6 boys and 6 girls = arrangement of 12 people = 12!
If the boys and girls sit alternatively
The required probability in that case would be given by
= 2 . 6! . 6!/ 12!
= 1/462. answer...
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