6 boys and 6 girls go to an exhibition and the cost of a ticket is Rs 10. Each girl has a ten rupee note while each boy has twenty rupee note they stand in a queve at the counter and the cashier does not have any money in the beginning , then the number of ways of arranging the boys and girls ,so that no one waits for a change is.plese provide steps
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The number of ways of arranging the boys and girls, so that no one waits for a change is = 132 (6!)².
Step-by-step explanation:
Total number of outcomes = number of ways of arranging 6 persons in a queue = 6! = 720
Favourable outcomes = 5 (3! x 3!) =180
hence required probability = 180 / 720 = 1 / 4.
¹²C₆ / 7 ways the position of boys and girls can be arranged.
Among the girls, arrangements are 6! .
Among the boys are 6! .
Hence the number of ways is = 132 (6!)².
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