Question

6 by 3 root 2 - 2 root 3 = a root 2 - b root 3 find a and b​

Answer 1

Step-by-step explanation:

$\frac{6}{3 \sqrt{2} } - 2 \sqrt{3} = a \sqrt{2} - b \sqrt{3}$

$( \frac{6}{3 \sqrt{2} } \times \frac{3 \sqrt{2} }{3 \sqrt{2} } ) - 2 \sqrt{3} = a \sqrt{2} - b \sqrt{3}$

$\frac{6 \times 3 \sqrt{2} }{9 \times 2} - 2 \sqrt{3} = a \sqrt{2} - b \sqrt{3}$

$\frac{18 \sqrt{2} }{18} - 2 \sqrt{3} = a \sqrt{2} - b \sqrt{3}$

$\sqrt{2} - 2 \sqrt{3} = a \sqrt{2} - b \sqrt{3}$

$a = 1$

$b = 2$

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