Question

6 by 3 root 2 minus 2 root 3

Answer 1

Answer :

$\frac{6}{3 \sqrt{2} - 2 \sqrt{3} } \\ \\ here \: we \: have \: to \: rationalise \: the \: denominator \\ \\ = > for \: rationalising \: the \: denominator \\ multiply \: the \: denominator \: with \: itself \: \\ and \: the \: numerator \: and \: change \: its \: sign\\ \\ = > \: \frac{6}{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } \\ \\ = > use \: the \: identity \: \\ \\ (a - b)(a + b) = {a}^{2} - {b}^{2} \\ \\ \frac{6(3 \sqrt{2} + 2 \sqrt{3} )}{(3 \sqrt{2}) {}^{2} - (2 \sqrt{3} ) {}^{2} }$

$= > \frac{6(3 \sqrt{2} + 2 \sqrt{3} )}{9 \times 2 - 4 \times 3} \\ \\ = > \frac{6(3 \sqrt{2} + 2 \sqrt{3} ) }{18 - 12} \\ \\ = > \: \frac{6(3 \sqrt{2} + 2 \sqrt{3}) }{6} \\ \\ = > cut \: 6 \: with \: 6 \\ \\ = > 3 \sqrt{2} + 2 \sqrt{3}$

HOPE IT WOULD HELP YOU

Answer 2

Answer:

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