Math, asked by fatimatanzeem82, 12 days ago

6 by root5+root2 rationalize the denominator​

Answers

Answered by bagkakali
0

Answer:

6/(√5+√2)

=6(√5-√2)/(√5+√2)(√5-√2)

=6(√5-√2)/(√5^2-√2^2)

=6(√5-√2)/(5-2)

=6(√5-√2)/3

=2(√5-√2)

Answered by NewGeneEinstein
1

Step-by-step explanation:

 \tt \longmapsto \:  \frac{6}{ \sqrt{5} +  \sqrt{2}  }  \\  \\  \tt \longmapsto \:  \frac{6( \sqrt{5} -  \sqrt{2} ) }{( \sqrt{5}  +  \sqrt{2})( \sqrt{5}  -  \sqrt{2} ) }  \\  \\  \tt \longmapsto \:  \frac{6 \sqrt{5}  - 6 \sqrt{2} }{( \sqrt{5}  {)}^{2}  - ( \sqrt{2} ) {}^{2} }  \\   \\ \tt \longmapsto \:  \frac{6 \sqrt{5}  -  6\sqrt{2} }{5 - 2}  \\  \\  \tt \longmapsto \:   \frac{6 \sqrt{5} - 6 \sqrt{2}  }{3}  \\   \\ \tt \longmapsto \:  \frac{6( \sqrt{5}  -  \sqrt{2}) }{3}  \\  \\  \tt \longmapsto \:  \frac{ 2(\sqrt{5} -  \sqrt{2} ) }{1}  \\  \\  \tt \longmapsto \: 2\sqrt{5}  - 2\sqrt{2}

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