Question

6 by root5+root2 rationalize the denominator​

Answer 1

Answer:

6/(√5+√2)

=6(√5-√2)/(√5+√2)(√5-√2)

=6(√5-√2)/(√5^2-√2^2)

=6(√5-√2)/(5-2)

=6(√5-√2)/3

=2(√5-√2)

Answer 2

Step-by-step explanation:

$\tt \longmapsto \: \frac{6}{ \sqrt{5} + \sqrt{2} } \\ \\ \tt \longmapsto \: \frac{6( \sqrt{5} - \sqrt{2} ) }{( \sqrt{5} + \sqrt{2})( \sqrt{5} - \sqrt{2} ) } \\ \\ \tt \longmapsto \: \frac{6 \sqrt{5} - 6 \sqrt{2} }{( \sqrt{5} {)}^{2} - ( \sqrt{2} ) {}^{2} } \\ \\ \tt \longmapsto \: \frac{6 \sqrt{5} - 6\sqrt{2} }{5 - 2} \\ \\ \tt \longmapsto \: \frac{6 \sqrt{5} - 6 \sqrt{2} }{3} \\ \\ \tt \longmapsto \: \frac{6( \sqrt{5} - \sqrt{2}) }{3} \\ \\ \tt \longmapsto \: \frac{ 2(\sqrt{5} - \sqrt{2} ) }{1} \\ \\ \tt \longmapsto \: 2\sqrt{5} - 2\sqrt{2}$