Question

6. Calculate
(i) the compound interest for the IInd year on 15,000 invested for 3 years at 8% per annum.
(ii) the sum due at the end of IIIrd year.​

Answer 1

p = 15000

T = 3year

R = 8%

15000(1 + 8/100) ³

15000 × 108/100×108/100×108/100 =

18895.680

naxt one year / lllrd year is used in

s.i. formula.

18895.680 × 5 × 1

(---------------------------) = ?

100

Answer 2

Answer:

the compound interest 2nd year=15000

I=pnr÷100

here for first year

p=15000

n=1st year

r=8%

so I=15000×1×8÷100=1200

lllrd year=15000+1200=16200=p

n=3rd year

r=8%

so I= 16200×3×8÷100

=3888