Question

6.Calculate the electric field intensity due to a point charge 20uCat a point distant 40 cm from the


charge?
(1.125 x 10-NC-]​

Answer 1

Answer:

point charge=20 micro couloumb =20 × 10^-6

r=40cm=40×10^-2 m

E=1/4π∈o×(q/r^2)

E=9×10^9×((2×10^6)÷(40×10^-2))=112500n/c