Question

6.Calculate the number of Moles of Cu(C2H3O2)2 present in 200 g *
2 points
1.1 mol
1 mol
.9 mol
1.2 mol

Answer 1

$\Large{\underline{\underline{\red{\tt{\purple{\leadsto } GiveN:-}}}}}$

• Given mass to us is 200 g .
• The compound is $\sf Cu(C_2H_3O_2)_2$

$\Large{\underline{\underline{\red{\tt{\purple{\leadsto } To\:FinD:-}}}}}$

• The Number of moles.

$\Large{\underline{\underline{\red{\tt{\purple{\leadsto } FormulA\:UseD:-}}}}}$

We can calculate number of moles when weight is given and a molecule as :

$\underline{\orange{\boxed{\purple{\bf{\dag\:\:n(Moles)\:\:=\:\:\dfrac{Given\:Weight}{Molecular\:Weight}}}}}}$

$\Large{\underline{\underline{\red{\tt{\purple{\leadsto } AnsweR:-}}}}}$

First of all let's calculate the molecular mass ,

So , atomic mass of used compounds are ,

• $\sf Carbon = 12g$
• $\sf Copper = 64g$
• $\sf Hydrogen = 1g$
• $\sf Oxygen = 16g$

$\tt Hence\: molar\: mass\:will\:be:$

=$\sf 64g +2 ( 12 \times2+1\times3+16\times2)g$

=$\sf 64g +2(24+3+32)g$

=$\sf 64g + 2\times 59$

=$\sf 64g + 118g$

=$\sf 182g$

$\bf Now\: put\:the\:values\:in\: above\: formula\:stated:$

$\tt:\implies n(Moles)=\dfrac{Given\:mass}{Molecular\:mass}$

$\tt:\implies n(Moles)=\dfrac{200g}{182g}$

$\underline{\boxed{\red{\tt\longmapsto \:\:n(Moles)\:\:=\:\:1.09}}}$

$\boxed{\green{\bf\purple{\dag}\:Hence\:the\: Number\:of\: moles\:is\:1.09.}}$

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$\underline{\pink{\sf{\leadsto MORE\:RELATED\: INFORMATION:-}}}$

$\green{\bf \orange{\bullet} Mole:-}$

It is a measuring unit which contains as many entities as contained in in 1/12 part of C- 12 isotope. its its value is equal to 6.022 × 10²³.

$\green{\bf \orange{\bullet} Avogrado's\: Number:-}$

The value of Avogrado's Number is 6.022 × 10²³.

It is used to find number of moles , Atoms , Molecules , Ions , etc.

Answer 2

Given:

The compound is $Cu(C_{2}H_{3}O_{2})_{2}$.

To find:

Moles of this compound in 200 gram sample?

Calculation:

• First , lets find out the molar mass.

Molar mass = 64 + 2[(2×12)+(1×3)+(16×2)]

=> Molar mass = 64 + 2[24 + 3 + 32]

=> Molar mass = 64 + 2[59]

=> Molar mass = 64 + 118

=> Molar mass = 182 g/mol

Now, moles will be :

$\therefore \: moles = \dfrac{200}{182} = 1.09 \: mol$

$\therefore \: moles\approx 1.1\: mol$

So, total number of moles is 1.1 .