6. Calculate the number of protons in 34 mg, NH, at
N.T.P.
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The molar mass of NH3 is 17g. Therefore we will first calculate the number of moles in 34mg (or 0.034 g) of ammonia.
Number of moles in 0.034 g of NH3 = mass / molar mass
= 0.034 / 17 = 0.002 moles
Now 1 mole of NH3 = 6.023 X 1023 molecules of NH3
Therefore 0.002 moles of NH3 = 0.002 X 6.023 X 1023 molecules of NH3
= 1.2046 X 1021 molecules of NH3
Now 1 molecule of NH3 contains 10 protons (7 from nitrogen and 3 from hydrogen).
Therefore 1 molecule of ammonia = 10 protons
and 1.2046 X 1021 molecules of ammonia = 1.2046 X 1021 X 10 = 1.2046 X 1022 protons
hope it helps you...
Number of moles in 0.034 g of NH3 = mass / molar mass
= 0.034 / 17 = 0.002 moles
Now 1 mole of NH3 = 6.023 X 1023 molecules of NH3
Therefore 0.002 moles of NH3 = 0.002 X 6.023 X 1023 molecules of NH3
= 1.2046 X 1021 molecules of NH3
Now 1 molecule of NH3 contains 10 protons (7 from nitrogen and 3 from hydrogen).
Therefore 1 molecule of ammonia = 10 protons
and 1.2046 X 1021 molecules of ammonia = 1.2046 X 1021 X 10 = 1.2046 X 1022 protons
hope it helps you...
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