Question

6. Calculate ZAOC, ZBOD and ZAOE in the given
figure, if it is given that ZCOD = 90°, ZBOE =72°
and AOB is a line.​

Answer 1

Step-by-step explanation:

3x + 72° = 180° ( given AOB is a line)

3x = 180°- 72°

3x= 108

x= 108°/3

x= 36°

angle AOE= 3(x) = 3(36°)=108°

angle AOC + angle COD + angle DOB = 180

x + 90° + y= 180°

36° + 90° + y= 180°

y = 180° - 90° - 36°

y = 180° - 126°

y= 54°

therefore, angle DOB= 54°.