6. Consider a 100-watt bulb radiating uniformly, suppose that the energy radiated by the bulb is 10% of the input power. This radiation is incident on a potassium surface that is 50 cm away from the bulb. Treating each potassium atom as a circular disk of diameter 1A. determine the time required for each atom to absorb an amount of energy equal to its work function of 2.0 eV, according to wave interpretation of light.
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Answer:
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Explanation:
(a) λ=589×10
−9
m
Energy per photon is given by, E=
λ
hc
E=
589×10
−9
6.6×10
−34
×3×10
−8
=3.37×10
−19
J or 2.11eV.
(b) P=100W
Let n no. of photons delievered to this sphere.
So, P=nE
⇒n=
3.37×10
−19
100
=2.96×10
20
photon/second
Answered by
0
Answer:
Answer:
it might help you
Explanation:
(a) λ=589×10
−9
m
Energy per photon is given by, E=
λ
hc
E=
589×10
−9
6.6×10
−34
×3×10
−8
=3.37×10
−19
J or 2.11eV.
(b) P=100W
Let n no. of photons delievered to this sphere.
So, P=nE
⇒n=
3.37×10
−19
100
=2.96×10
20
photon/second
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