Math, asked by keshavsahod, 1 month ago

6) Construct a quadrilateral ABCD in which AB = 4 cm. BC = 5 cm, CD = 5.5 cm,
DA = 4.5 cm and diagonal AC = 6 cm. Also construct a triangle ADE equal in area to the quadrilateral​

Answers

Answered by Itzsweetcookie
2

Answer:

good \: evening \:  +  \: thank

Answer

Steps of construction are given below :

⇒  Draw line segment BC of length 4.5cm.

⇒  With C as a center and radius CD = 5cm draw an arc.

⇒  With B as a center and radius BD = 7cm draw an arc intersecting the previous arc at D.

⇒  Again with C as the center and 5.5cm as a radius draw an arc.

⇒  Then with D as the center and 5.5cm as radius, draw an arc intersecting the point at A.

⇒ Join AB, AD, CD, BD, and AC.

Thus, ABCD is a required quadrilateral. 

Attachments:

keshavsahod: hey where is the triangle?? in the figure
Itzsweetcookie: all the dotted lines are the triangle see
keshavsahod: can't you see the question properly i need to construct triangle ADE which area is equal to the quadrilateral where is triangle ADE??
Itzsweetcookie: e is the centre that is not marked
keshavsahod: i don't understand clearly can you give me your facebook id
keshavsahod: i want to learn from you
keshavsahod: can you teach me now?
keshavsahod: hey you plz reply
keshavsahod: hey you why not replying?
Answered by ItzMissKomal
0

Answer:

Steps of construction are given below :

⇒ Draw line segment BC of length 4.5cm.

⇒ With C as a center and radius CD = 5cm draw an arc.

⇒ With B as a center and radius BD = 7cm draw an arc intersecting the previous arc at D.

⇒ Again with C as the center and 5.5cm as a radius draw an arc.

⇒ Then with D as the center and 5.5cm as radius, draw an arc intersecting the point at A.

⇒ Join AB, AD, CD, BD, and AC.

Thus, ABCD is a required quadrilateral.

Attachments:
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