Question

6. Correct order of increasing solubility in water of RbI, CdI2 and PbO2 is
1) PbO2, CdI2, RbI 2) RbI, CdI2, PbO2
3) CdI2, PbO2, RbI 4) PbO2, RbI, CdI2
please write the proof

Answer 1

The correct order of increasing solubility in water is  :

(1) PbO2, CdI2, RbI

- Lead dioxide (PbO2) is insoluble in water.

- Cadmium iodide (CdI2) has comparatively low solubility of around 850 g/L in water.

- Rubidium iodide (RbI) has high solubility of almost 1500 g/L in water.

- So the correct order of solubility in water is PbO2 < CdI2 < RbI.