(6) cos⁴q-sin⁴q = ? what is value
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Answer:
cos2q
Step-by-step explanation:
The given expression can be written as
- (cosq²)²-(sinq²)²
- a²-b²=(a+b)(a-b) we know this apply this in step 1
- that is (cosq²)²-(sinq²)²=(cos²q+sin²q)(cos²q-sin²q)
- =1(cos²q-sin²q). { Since by using identity cos²q+sin²q=1}
- =cos2q. {because cos2q=cos²q-sin²q we have this formulae too}
- hence cos2q is answer for the Question
I hope it's CLEAR ✌️
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