Question

6. Current 'i' coming from the battery and
ammeter reading are
402
402
40​

Answer 1

Explanation:

Correct option is

A

8

3

A,

8

1

A

All three 4Ωresistors are in parallel .Assume ammeter is ideal :

So current in all resistors will be divided and current will

3

i

Net Resistance =

3

4

+4

=

3

16Ω

i=

R

eq

V

=

16

2

×3

=

8

3

A

Ammeter reading =

3

i

=

3

1

×

8

3

=

8

1

A

solution