Question

6.
(d) 10/2 cm
24 m लम्बी, 3 m ऊँची तथा 60 cm चौड़ी दीवार बनाने के
लिए 24 cm लम्बी, 12 cm चौड़ी तथा 8 cm ऊँची कितनी
ईंटे लगेंगी, जबकि दीवार के कुल आयतन का 10% भाग
सीमेंट तथा रेत के मिश्रण से बना हो?​

Answer 1

Step-by-step explanation:

for wall:-

L = 24m, B = 3m, H = 0.6m

therefore, Volume of cuboidal wall = L*B*H = (24*3*0.6) m^3 = 43.2 m^3

Now, For Bricks :-

l = .24m, b= .12m, h = .08m

therefore, volume of cuboidal bricks = l*b*h

= (.24×.12×.08) m^3 = 0.002 m^3

Now, for total no. of bricks;

n(volume of Cuboidal brick) + 10%(volume of wall) = Volume of Cuboidal wall

n(0.002) + 4.32 = 43.2

n(0.002) = 43.2-4.32

n(0.002) = 38.88

n = 38.88/0.002

n = 19,440.

therefore, total no. of bricks used = 19,440.