Question

6. D is a point in side BC of triangle ABC. If
AD > AC, show that AB > AC.​

Answer 1

In triangle DAC,
AD=AC ( given)
So , angle ADC =angle ACD (angles opposite
to equal sides)
Now, angle ADC is an exterior angle for triangle ABD.

So, angle ADC is greater than angle ABD

or., angle ACD is greater than angle ABD

or, angle ACB is greater than angle ABC

So, AB is greater than AC ( Side opposite to
larger angle in triangle ABC)

or, AB is greater than AD (AD =AC).