Question

6. Determine the dimensions of cross-section of
the connecting rod for a diesel engine with
the following data :
Cylinder bore - 100 mm;
Length of connecting rod - 350 mm;
Maximum gas pressure - 4 MPa;
Factor of safety - 6.
Determine the dimensions of small and big
end bearings of the connecting rod for a
diesel engine with the following data :
(Length,l /diameter, d) ratio for
piston pin bearing - 2;
(Length,l /diameter, d) ratio for
crank pin bearing - 1.3;
Allowable bearing pressure for
piston pin bearing - 12 MPa;
Allowable bearing pressure for
crank pin bearing = 7.5 MPa.​

Answer 1

Answer:

7.58 is answer please mark me as brainlist

Answer 2

Answer:

value of t is 7.58mm approx=8

b=4*8=32mm

H=5*8=40mm

Step-by-step explanation:

cylinder bore cross section=100mm

Length of connecting rod - 350 mm;

Maximum gas pressure - 4 MPa;

Factor of safety - 6.

step1: force acting on rod

$p_{c} = \frac{\pi {d}^{2} }{4} p_{max}$

$= \frac{\pi {100}^{2} }{4} \times 4$

$= 31415.93$

step2: critical bulking of load

$p_{cr} = p_{c} \times f_{s}$

$= 31415.93(6) = 188495.58$

critical bulking of load is 188495.58N

calculating t

$A = 11 {t}^{2}$

$k_{xx} = 1.78t$

$a = \frac{1}{7500}$

$σ_{c} = 330 \frac{n}{ {mm}^{2} }$

$p_{cr}  = \frac{σ_{c} a}{1 + a( \frac{l}{kxx} ) {}^{2} }$

$188495.58 = \frac{330(11 {t}^{2} )}{1 + \frac{1}{7500} ( (\frac{350}{1.78}) ^{2} }$

$\frac{ {t}^{4} }{ {t}^{2} + 5.16 } = 51.93$

roots for quadratic equation

${t}^{4} - 51.93 {t}^{2} - 267.96 = 0$

so

${t}^{2} = \frac{51.93 + - \sqrt{ {51.93}^{2} - 4(1)( - 267.96)} }{2}$

${t}^{2} = 56.66$

value of t is 7.58mm approx=8

b=4*8=32mm

H=5*8=40mm

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