Question

6. Diagonal AC of a parallelogram ABCD bisects
angle A(see Fig. 8.19). Show that
(i) it bisects < C also,
(ii) ABCD is a rhombus.

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Answer 1

$\mathbb\green{AB=AD \: by \: cpct} \: \mathbb\blue{BC = CD \: by \: cpct} \: </p><p>\mathbb\purple{AD=BC \: opp. \: sides \: are \: equal} \: \mathbb\green{AB=BC=CD=AD} \: \: \mathbb\red{Hence,ABCD \: is \: a \: rhombus}$

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