Question

6. Divide.
(32x^4 y^3- 16x^3y^4) by (-8x^2y)
please answer with images full solutions
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Answer 1

$\rm\: (32x^4 y^3- 16x^3y^4) \: by \: (-8x^2y)$

$\rm \: \frac{32x^4 y^3- 16x^3y^4 }{ -8x^2y}$

$\rm \: \rm \: \frac{ - (32x^4 y^3- 16x^3y^4 )}{ 8x^2y}$

$\rm \: \frac{ - 32x^4 y^3 + 16x^3y^4 }{ 8x^2y}$

$\rm \: \frac{16 {x}^{3} {y}^{3} (- 2x+ y )}{ 8x^2y}$

$\rm \: {2x {y}^{ {2} } (- 2x+ y )}$

$\rm \: { - 4 {x}^{2} {y}^{ {2} } + 2x {y}^{3} )}$

$\mathfrak{ so \:the \: answer \: is \: - 4 {x}^{2} {y}^{ {2} } + 2x {y}^{3} }$

Answer 2

Step-by-step explanation:

Start with the conversion factor between pounds and kilograms. 1 kg = 2.2 lbs ... weight in kg = weight in lb x (1 kg / 2.2 lb) ... It's easy to work the conversion the other way, too. If given a ...