Question

6. Divide 63(p4 + 5p3 – 24p2) by 9p(p + 8).
Solve

Answer 1

Hence the solution of 63(p4 + 5p3 – 24p2) divided by 9p(p + 8) is 7p(p-3).

Step-by-step explanation:

Given:

We have,

$\frac{63(p^4 + 5p^3 - 24p^2)}{ 9p(p + 8)}$

=$\frac{63p^2(p^2 + 5p - 24)}{9p(p + 8}$

=$\frac{7p(p^2 + 5p - 24)}{(p + 8)}$

Splitting the middle term, we get

=$\frac{7p(p^2 + 8p-3p - 24)}{(p + 8)}$

=$7p[\frac{p(p+8)-3(p+8)}{(p+8)} ]$

=$7p[\frac{(p+8)(p-3)}{p+8}]$

=7p(p-3)

Hence the solution is 7p(p-3).

Answer 2

Answer:

hope it will be helpful...