Math, asked by bhavaniedara5879, 8 months ago

6 Divide Rs.300 into two parts such that helf of one
part may be less then the sider by 48.
A
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Answers

Answered by manishaprajapati1891
1

Answer:

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Answered by AbhayTHEking
1

Answer:

6 Divide Rs.300 into two parts such that helf of one

part may be less then the sider by 48.

Step-by-step explanation:

the 1st number = x

The second number = 300 - x

If we take 1/2 x, it must be 48 less than the other part, which is (300 - x) - 48

We have the following equation then:

1/2 x = 252 - x

3/2 x = 252

3x = 504

x = 168

The other part is 300 - x = 300 - 168 = 132

If we take 1/2 of 168, we get 84

132 - 48 = 84

So, our solution is correct

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