Math, asked by sumitkumarjihai, 6 months ago

6. Divide the sum of (-1÷2)^-2
and (-1÷3)^-2
by the difference of (1÷5)^-1
and (1÷4)^-1.​

Answers

Answered by hasthalapurampoornim
4

Step-by-step explanation:

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Answered by pukultanvi4444
6

Answer:

sum of (-1÷2)^-2

and (-1÷3)^-2

(−1/2)−2+(−1/3)−2

=4+(−1/3)−2

=4+9

=13

difference of (1÷5)^-1

and (1÷4)^-1.

(1/5)−1−(1/4)−1

=5−(1/4)−1

=5−4

=1

Divide 13/1

13/1

=13

Step-by-step explanation:

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