6. double c;int x,y,z; x=5;y=10;z=11; c=x*y+z/2; The value stored in c is:
(a) 55.0
(b) 55.5
(c) 55
(d) none
Answers
Answered by
6
Answer:
55
Explanation:
Hopefully it helps!
Answered by
9
Explanation:
c=5*10+11/2
c=(100+11)/2
c=55.5
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