6. Equation of motion of projectile in x-y plane is
y = ax - bx^2, then the angle of projection with
x-axis is
[NCERT Pg. 78]
(1) tan^-1 (b)
(2) tan^-1(a)
(3) cos^-1(b)
(4) sin^-1(a)
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Answer:
The range of the projectile is ab
At x=a2b , the velocity of projectile becomes zero
The maximum height attained by projectile is a24b
The angle of projection is tan−1(a)
Answer :
A::C::D
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Explanation:
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