Question

6. Evaluate :
(iii) sin 135ºcos145° + cos 135ºsin1450​

Answer 1

Step-by-step explanation:

Its really a good question

As per the formula,

Sin.A Cos.B + Cos.A Sin.B = Sin ( A+B )

Thus,

sin 135ºcos145 + cos 135ºsin145° = Sin(135°+145°)

==> Sin (280°) ==> (-0.98480)

Well, 280° is not a standard angle but you can also check the question once again since it could go easy if one of the angle is 45° instead of 145° OR 35° instead of 135°

Then you get the answer as follows.

Sin.A Cos.B + Cos.A Sin.B = Sin ( A+B )

sin 135ºcos45 + cos 135ºsin45° = Sin(135°+45°)

==> Sin (180) ==> 0

IF YOU THINK I WAS RIGHT THEN PLEASE MARK IT AS THE BRAINLIEST ANSWER